Short Question of #Physics #ctvet

 

Q.1 OBTAIN THE DIMENSIONAL FORMULA OF UNIVERSAL GRAVITIONAL CONSTANT AND SPECIFIC HEAT CAPACITY

ANS. The dimensional formula for the universal gravitational constant (G) is [M^-1 L^3 T^-2].

The dimensional formula for the specific heat capacity (C) is [M L^2 T^-2 K^-1].

Q.2 HOW DOES A SHOTPUT PLAYER PROJECT A BALL ,SO THAT HE COULD GET A MAXIMUM ANGLE ? EXPLAIN . 

 ANS. The range of a projectile for a given initial velocity is maximum when the angle of projection is 45∘..

Q.3 WHAT IS PROJECTILE ? SHOW THAT THE PATH OF PROJECTILE IS PARABOLIC .

ANS. A projectile is an object that is given an initial velocity and then follows a path determined by the laws of physics, such as gravity. Examples of projectiles include bullets, arrows, and thrown objects.

Q.4 A BODY IS PROJECTED UPWORD MAKING AN ANGLE OF 60 DEGREE WITH VERTICAL AXIS AT THE VELOCITY OF 72KM/HR ,CALCULATE THE TIME OF FLIGHT IT ATTAINS . USE A g=10m/s`2

ANS. To calculate the time of flight, we need to determine the vertical component of the velocity (Vy) and use the formula:

Time of flight = 2 * Vy / g

To find Vy, we can use the trigonometric relationship:

Vy = V * sin(angle)

where V is the initial velocity (72 km/hr), and angle is the angle of projection (60 degrees).

Converting 72 km/hr to m/s:

V = 72 * 1000 / 3600 = 20 m/s

Using the sin function:

Vy = 20 m/s * sin(60) = 10 m/s

Now we can use the formula for time of flight:

Time of flight = 2 * Vy / g = 2 * 10 / 10 = 2 seconds

So the time of flight is 2 seconds.

Q.5 State and prove the principle of conservation of linear momentum .

ANS.  The principle of conservation of linear momentum can be applied to a wide range of physical phenomena, from simple collisions between objects to more complex interactions involving multiple objects and forces. In the case of a collision between two objects, for example, the conservation of linear momentum can be used to predict the motion of the objects before and after the collision.

Consider two objects, A and B, with masses m₁ and m₂, and initial velocities v₁ and v₂. The initial momentum of the system is the sum of the momentum of each object:

p₁ = m₁v₁ + m₂v₂

After the collision, the objects will have different velocities, v₁' and v₂', but the total momentum of the system will still be the same:

p₂ = m₁v₁' + m₂v₂'

Therefore, according to the principle of conservation of linear momentum, we have:

p₁ = p₂

This equation can be used to solve for the velocities of the objects after the collision, given their initial velocities and masses.

In summary, the principle of conservation of linear momentum states that the total momentum of an isolated system remains constant unless an external force is applied. This principle has many applications in physics and engineering, and can be used to predict the motion of objects before and after collisions and other interactions.

Q. 6  state newtons law of motion and prove that second law of motion give the measurement of force 

ANS.  Newton's laws of motion are a set of three physical laws that describe the motion of objects and how they are affected by forces. The second law, also known as Newton's second law of motion, states that the acceleration of an object is directly proportional to the net force acting on the object, and inversely proportional to its mass. Mathematically, it can be written as:

F = ma

Where F is the net force acting on the object, m is the mass of the object, and a is the acceleration of the object.

To prove that the second law of motion gives the measurement of force, we can consider an object with a known mass, and measure its acceleration in response to a known force. By substituting the known values into the equation F = ma, we can calculate the value of the force.

For example, consider an object with a mass of 5 kg, and an acceleration of 2 m/s^2. If we know that the force acting on the object is 20 N, we can substitute these values into the equation and check that it holds:

F = ma = 5 kg * 2 m/s^2 = 10 N

This confirms that the equation F = ma gives the measurement of force, as the calculated value of force matches the known value.

It is important to note that the net force acting on the object is the sum of all the forces acting on the object, including friction, air resistance and any other forces. And Newton's second law of motion only gives the measurement of net force acting on the object.

In summary, Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on the object, and inversely proportional to its mass. This equation can be used to measure the force acting on an object, given its mass and acceleration.

Q,   Can a physical quantity have unit but is dimensionless 

ans .      Yes, a physical quantity can have a unit but be dimensionless. A dimensionless quantity is a physical quantity that does not have any units of length, mass, or time. Instead, it is expressed as a ratio of two quantities with the same dimensions. The resulting value is a pure number with no units.

In summary, a physical quantity can have a unit but be dimensionless. Dimensionless quantities are physical quantities that are expressed as a ratio of two quantities with the same dimensions, resulting in a pure number with no units.

yes, A physical quantity have unite but no dimension .these are dimensionless quantities ,some of which have unit . 

Q. Name any two physical quantity which have same which have same dimension can a physical quantity but no dimension explain

A physical quantity that has no dimension is a dimensionless quantity. The physical quantities that have no dimension are those that are ratios of two quantities with the same dimension. For example, the ratio of an object's final velocity to its initial velocity is a dimensionless quantity. Both velocities have the units of length per time, so when we divide the final velocity by the initial velocity, the units cancel out, leaving a dimensionless ratio.

Q. A students write time period of simple pendulum is t = 2π √(l/g) is he correct check by dimensional method

Ans .   The student's statement that the time period of a simple pendulum is t = 2π √(l/g) is not correct when checked by dimensional analysis method.

The time period of a simple pendulum is the time it takes for the pendulum to complete one full oscillation. The correct equation for the time period of a simple pendulum is:

t = 2π √(l/g)

Where t is the time period, l is the length of the pendulum, and g is the acceleration due to gravity.

When we use dimensional analysis method to check the equation, we find that the units of the right-hand side of the equation do not match the units of the left-hand side. The unit of time period is seconds (s), the unit of length is meter (m) and the unit of acceleration due to gravity is m/s^2.

The right-hand side of the equation can be rewritten as:

t = 2π √(l/g) = 2π √(m/m/s^2) = 2π √(m^2/s^2)

And the left-hand side of the equation is simply s.

As we can see the units of left-hand and right-hand side of the equation are not same, so the equation is dimensionally incorrect and the statement of the student is not correct.

The correct equation for the time period of a simple pendulum is:

t = 2π √(l/g)

Where l is the length of the pendulum and g is the acceleration due to gravity.

It is important to note that when checking an equation using dimensional analysis, all quantities must be expressed in terms of their base units (such as meters, kilograms, and seconds), and the units on both sides of the equation must match.